JEE Main 2019: Online application from 1st September, 2018
National Testing Agency an autonomous organization under the Department of Higher Education, Ministry of Human Resource Development, Government of India, with registered Office at West Block-1, Wing No. 6, 2" Floor. R K Puram, New Delhi-110066, will hold the Joint Entrance Examination (Main) January 2019, between 6th January 2019 and 20th January 2019.
JEE (Main) -January 2019, is the first of the two examinations to be conducted by the NTA for admission to the BE/B Tech and B Arch/B Planning Programmes at National Institute of Technology (NIT), Indian Institute of Information Technology (IIIT) and Centrally Funded Technology Institutes (CFTIs) participating though Central Seat Allocation Board. Those seeking admission through JEE (Main), can apply either for appearing for this entrance in the month of January or that in April or in both of these, as per their convenience and apply for admission with the better JEE Main score. However, it is not necessary that one should appear in both the JEE (Main) - January 2019 and JEE (Main) - April 2019 sessions.
The second JEE (Main) - April 2019 will be conducted between 6th April 2019 and 20th April 2019 for which a separate notice will be issued later on and those interested will be required to apply separately. For the JEE (Main) 2019, April session, the application submission will be in the month of February, 2019. Application Form will be available for April Examination of JEE Main 2019 from 8th February, 2019 to 7th March, 2019.
Online application for the first Joint entrance Examination (JEE) Main 2019, January session, can be submitted at www.jeemain.nic.in by September 30, 2018.
Scheme of JEE Main: JEE (Main), January 2019, will be held between 6th January 2019 and 20th January 2019 as a Computer based Test. It will have 2 papers. Paper 1 is for admission to the B E/B Tech Programmes and will have 30 multiple choice, objective type questions each from Mathematics, Physics and Chemistry and the test will be held only in the Computer Based Test (CBT) mode in multiple shifts on the test days, the first being from 9.30 am to 12.30 pm and the second, from 2.30 pm to 5.30 pm.
Paper - 2 (For B. Arch/ B.Planning) (to be attempted in one sitting) will have 2 parts, with Mathematics (30 questions) in Part I and Aptitude Test (50 questions) in Part II, to be held in Computer Based Test (CBT) mode only with multiple choice, objective type questions. Part Ill will be the Drawing Test (2 questions with 70 marks), to be held in ‘Pen & Paper Based’ (offline) mode to be attempted on Drawing sheet. Paper -2 will be held in one shift only.
One may appear in Paper 1 and/or Paper 2 depending upon the course/s he/she wishes to pursue.
Scoring pattern: For Multiple choice questions, for each correct answer, 4 marks will be awarded and for each incorrect response, one mark will be deducted.
Screening for IITs: All those aspiring to take admission to the undergraduate programs at Indian Institutes of Technology (IlTs) for 2019-20 admissions, should appear in Paper-1 (B.E/B.Tech.) of JEE (Main)-2019. Based on the performance in Paper-1 (B. E. /B. Tech.) of JEE (Main)-2019, a specified number of top candidates as per the requirement of JEE (Advanced) (including all categories) will become eligible to appear in JEE (Advanced)-2019. Admissions to IlTs will be based only on category-wise All India Rank (AIR) in JEE (Advanced), subject to conditions as defined in JEE (Advanced)-2019 website.
Admission requirements: For admission to B.E./B.Tech. Courses in NITs, IIITs and other CFTIs, applicant should have passed the 10+2 examination with Physics and Mathematics as compulsory subjects along with one of Chemistry/Biotechnology/Biology/ Technical Vocational subject. For admission to B.Arch./Planning, applicant should have passed 10+2 examination with Mathematics.
Application Fee: Application fee for General/OBC applicants appearing for one paper in a Centre in India would be Rs.500/- For SC/ST/ PwD and Girl applicants, if opting for an examination centre in India, it would be Rs.250/-. For those appearing for both papers in an examination centre in India, the fee would be Rs.1300/- for UR and OBC and Rs.650/- for PwD/SC/ST/Girls. If opting for an examination Centre outside India, it would be Rs. 2500/-and Rs.1250/- for one paper and Rs.3800/- and Rs.1900/-for two papers (UR/OBC and SC/ST/PwD/Girls respectively). Fee can be paid using Credit Card/Debit Card/Net Banking. The fees can be paid online up to 1st October, 2018.
Applicants should keep ready, Mark sheets of class 10 and 12, AADHAR card, Passport size photograph, Signature of both the candidate and of the guardian, Caste Certificate (if applicable), Income Statement, Category Statement (if applicable) etc; before submitting applications so that the application Form could be filled on time. Some of them will be needed by the applicants for the purpose of reference and other, needs to be uploaded.
Eligibility for JEE (Main) 2019: There is no age limit for appearing for JEE (Main) 2019. Applicant should however, satisfy themselves about the eligibility of age limit requirements of the Institutes in which he/she is desirous of taking admission.
Applicant should have passed their Class 12th Examination or any equivalent qualifying examination in 2017 or 2018 or should be appearing in their Class 12th Examination or any equivalent qualifying examination in 2019. Those who passed Class 12th/Qualifying examination in 2016 or before as well as those who will appear in such examination in 2020 or later are not eligible to appear in JEE- Main, 2019.
Applicant must have taken at least five subjects in class 12th/qualifying examination. Those who have taken four subjects are not permitted to write JEE (Main) – 2019.
Answer Key/Response: After the JEE (Main)-2019 examinations, the NTA will display Answer Keys & recorded responses of multiple choice questions of Paper-1 and Paper-2 on the NTA’s website www.jeemain.nic.in on a date to be announced on NTA website.
Those who are not satisfied with the recorded response may challenge the same, by filling online application form and paying a sum of Rs.1000/- per response challenged. Applicants can also challenge the answer keys also online through the link available at www.jeemain.nic.in on payment of Rs.1000/- per answer key challenged. The fee for challenges can be paid by credit/debit card.
Evaluation of multiple choice questions of Paper-1 and Paper-2 will be carried out using final answer keys and the raw (actual) marks obtained by a candidate will be considered further for computation of the result of JEE (Main)-2019. For multi-shift papers, raw marks obtained by the candidates in different shifts/sessions will be converted to NTA Score. The detailed procedure based on NTA Score being adopted is available on NTA website.
Ranking: In case of those who appeared in both the attempts; their best of the two NTA scores (total) will be considered for further processing. When two or more candidates obtain equal total NTA Score in JEE(Main)-2019, inter-se merit of such candidates shall be determined by considering NTA score of raw mark in Mathematics, NTA score of raw mark in Physics, NTA score of raw mark in Chemistry and then candidates older in age. If the resolution is not possible after this criterion, candidates will be given the same rank.
Since, JEE (Main)-2019 Paper-2 is conducted in single-shift, the raw marks obtained by all the candidates who appeared in first attempt will be declared by 31st January, 2019. This shall comprise the actual marks obtained in Paper-2 of JEE (Main)–2019 for the first attempt.
Similarly, Paper-2 of the second JEE (Main)-2019 attempt, may be conducted in single-shift. The raw marks obtained by all the candidates who appeared in second shift as well as for the first attempt will be merged for compilation of result and preparation of overall Merit List / Ranking. In case of those who have appeared in both the attempts; their best of the two raw marks will be considered for further processing. When two or more candidates obtain equal total Marks in Paper 2 of JEE(Main)-2019, inter-se merit of such candidates shall be determined by considering higher marks in Aptitude Test in Paper-2, higher marks in Drawing Test in Paper-2, age of applicant with the older person getting preference. If the resolution is not possible after this criterion, candidates will be given the same rank. The Total raw marks of both the attempts and rank of Paper-2 of JEE (Main)–2019 for all candidates who appeared in first attempt as well as in second will be declared by 30th April, 2019. This shall comprise the total raw marks obtained by the candidate in first attempt as well as in second attempt along with All India rank and All India category rank.
For more details, visit https://jeemain.nic.in/webinfo/Public/Home.aspx